Tests of ATM
Extreme
Load Tests
On
Electricity
GOD - ATM
As per Hindu Mythology our body
is made up of Panch Tatva (Five Elements) Akash(Space), Agni(Fire), Prithvi(Earth),
Jal(Water) and Vayu(Air). At the end of life,
the body is disintegrated back to these basic elements.
Electricity also has similar pattern.
Electricity is produced from basic source like Heat, Light, Wind, Water, Motion,
Height, Waves, Tide, Fire, Etc.
Above basic forms of energies is
converted to electrical energy by appropriate process. Electricity generating
systems are identified according to source of energy and conversion process as
Thermal Power Plant, Hydro Power Plant, Atomic Power Plant, Wind Power Plant,
Solar Power Plant etc.
Human
life has three stages Janma, Jivan and Nirvan. Janma is incarnation of life from
Panch Tatva. Lord Brahma is considered as regulator of this stage. Jivan is
life journey starting as infant and transform through various steps like baby,
toddler, child, teenage, young, adult, elder etc. During the life span, human move
to various places, meet others and have harmonious coexistence and interaction.
Lord Vishnu is considered as regulator of this stage. Nirvan is extinguishing
of life turning back to Panch Yatva. Lord Mahesh (Shiv) is considered as
regulator of this stage. Functionally load Brahma, Vishnu and Mahesh are
Generator, Operator and Destroyer of human life and known as GOD.
Electricity
also has similar life pattern. Its existence starts with conversion from basic
sources to electricity is known as Generation at power plant. Its life passes
through transmission and distribution network with transmission and transformation
to various forms, travel to various locations and meet others from different sources
and operate in synchronism during the T & D stage. At the end electricity
finally extinguish and converted to form required by user. These three stages
are Generation,
Transmission-Distribution
and Utilization
abbreviated as GTU.
There
are numbers of equipments in above three stages of power system. But Alternator, Transformer
and Motor (ATM) is
the most significant equipment representing GTU stages generation,
transmission-distribution and utilization.
Normally
all electrical equipments undergo different types of test at various stages. But
following pair of tests are common in all the above three by principal, objectives
and treatment.
Power
balance equation for any machine is known as under.
Power
Input = Power Output + Power Losses.
Iron Loss and Copper Loss are significant
losses whereas others losses like Dielectric, Stray, Friction and Windage
losses are insignificant and ignored for generally study.
So above equation stands
simplified as under
Power Input = Power Output +
Iron loss + Cupper loss.
The Equation further reduced when
machine output is zero.
Power Input = Iron loss +
Cupper loss.
Of various test for different purpose, the following tests are to estimate significant losses by extreme loading without output.
A. Extreme
Minimum load means zero Load.
B. Extreme
Maximum load can be infinite load but it is not feasible for safety of
equipment. So Maximum load is restricted to rated load.
Iron loss is in the magnetizing circuit and is proportional to square of applied voltage ( V2/X ) as it is across the supply in equivalent circuit.
Cupper Loss is in resistance of the coils and is proportional to square of load current ( I2R ) as it is in series with the load in equivalent circuit.
Ultimately above power balance
equation with no output at applied voltage Va and load current Ia
will be as under.
Power Input = Normal Iron Loss
(Va/Vr)2 + Normal Cupper Loss (Ia/Ir)2
Where
Va is applied
Voltage and Vr is rated voltage.
Ia is actual load current
and Ir is rated load current.
General Setup for Equipment Performance
Testing is as under.
It has following three elements.
a. Voltage Regulator Rheostat in DC OR Variac in AC
b. Power Measurement
For DC
supply - DC Wattmeter OR DC Voltmeter and DC Ammeter and P = V*I
AC 1ϕ Supply
– AC Wattmeter OR
AC
Voltmeter, AC Ammeter and PF meter and P= V*I*PF
AC 3ϕ Supply
– Three Phase Three Wire Wattmeter OR
Two
AC Watt meters P= W1+W2 OR
AC Voltmeter, AC Ammeter and PF meter P= √3* V*I*PF
Two Watt Meters Method
Current coil of W1 is connected in series in one of the phase.
Current
coil of W2 is connected in series in other phase
Pressure
coil of W1 and W2 is connected between respective phase and third phase.
W1 and
W2 have unequal reading except for Unity power factor.
W1 has backward
deflection at very low power factor. Leads of current coil or pressure coil have
to be reveres to read the meter and assign negative sign.
c. Mediator
and Auxiliary Devices – Depends what, when and where required
Output Block
It has following three elements.
a. Power Measurement Similar to input block
b. Loading
Devices Lamp Bank for Resistive Load – Unity Power Factor
Chock Coil for Inductive Load –
Lagging Power Factor
Capacitor Bank for Capacitive Load –
Leading Power Factor
Single
set for single phase load OR
Three
sets connected in star for three phase load.
c. Mediator
and Auxiliary Devices – Depends what, when and where required.
Now
Input Output power format of
above three representative equipments is as under.
Input |
Equipment |
Output |
Electrical |
Transformer |
Electrical |
Mechanical |
Alternator |
Electrical |
Electrical |
Motor |
Mechanical |
Test on Transformer Input
and Output are Electrical.
Test A Condition -> Secondary circuit open.
Known
as Open Circuit OR No load Test
Load side voltage is VL but current IL is Ia = 0
Output power = √3 × VL
× IL × PF = 0
Pin = Pout
+ Piron (Va/Vr)2 + Pcupper (Ia/Ir)2
Pin = o + Piron (Vr/Vr)2
+ Pcupper o/Ir)2
Power Input = Piron
Power input in this condition
is mostly Iron Loss
Test B Condition
-> Secondary circuit shorted. Known
as Short Circuit Test
High current may flow and damage
the machine. Therefore low voltage is applied to restrict load current to rated
value.
Actual load current Ia = Ir
Applied voltage Va is
very small and therefore (Va)2 is negligible
Output load current is Ir but voltage across
Short Circuited load VL = 0
So output = √3 × VL × IL × PF = 0
Pin = Pout
+ Piron (Va/Vr)2 + Pcupper (Ia/Ir)2
Pin = 0 + Piron (0/Vr)2
+ Pcupper (Ir/Ir)2
Pin = Pcupper
Power input in this condition
is mostly Cupper Loss
Test on Alternator Input
is Mechanical but Output is Electrical.
Test A Condition -> Similar to transformer. Output Circuit open.
Known as Open Circuit OR No load Test
Input power is mechanical and
is measured indirectly. Electric motor with known efficiency is used as prime mover.
Power drawn by motor is electrical and is measured as usual. Multiplying it by
its efficiency is output of motor and is the mechanical power input to
alternator. Generator is operated as normal with rated speed and voltage but output
circuit is kept open.
Power input in this condition is
mostly Iron Loss as in case of transformer.
Test B Condition -> Similar to transformer. Output
circuit shorted.
Known as Short Circuit Test
Under
this condition load current will be very high at normal output voltage and it
may damage the machine. Therefore output voltage is reduced by rheostat in
excitation circuit to restrict load current to rated value.
Power input in this condition is
mostly Cupper Loss as in case of transformer.
Test on Motor Input
is Electrical but Output is Mechanical.
Input Electrical power is
measured as usual.
Mechanical output power can be
measured by dynamometer OR Friction Belt method. But measurement is not
required as output power is kept zero as under.
Test A Condition -> Normal voltage is applied to motor and
allowed free
spin without any load connected. Known No Load Test.
Motor runs at normal angular
velocity ω (RPM). As motor is running freely, Torque T developed is insignificant
and actual Load Current Ia = IL
is also negligible.
So T and Ia taken as 0
In case of Leaner Motion
Work = Force × Distance
Work/time = Force × Distance/time
Power = Force ×Velocity
Similarly for Angular Motion
Power = Torque × Angular
Velocity i.e. P= T × ω
Now, Pin = Pout + Piron (Va/Vr)2
+ Pcupper (Ia/Ir)2
Pin = T × ω + Piron
(Va/Vr)2 + Pcupper (Ia/Ir)2
Pin = 0 × ω + Piron (Vr/Vr)2
+ Pcupper (0/Ir)2
Pin = Piron
Power input in this condition
is mostly Iron Loss
Test B Rotor of the motor is not allowed to spin is known
as Blocked Rotor Test.
In this condition heavy current
is expected and damage the motor.
Hence very voltage is applied
to limit the current to full load.
In this condition angular
velocity ω = 0 as rotor is blocked.
Actual current is rated current
Ia =IL
Applied voltage Va is
very small, hence (Va)2 is negligible.
Now Pin = Pout + Piron
(Va/Vr)2 + Pcupper (Ia/Ir)2
Pin = T × ω + Piron (Va/Vr)2
+ Pcupper (Ir/Ir)2
Pin = T × 0 + Piron (0/Vr)2
+ Pcupper (Ir/Ir)2
Pin = Pcupper
Power input in this condition is mostly Cupper
Loss
Conclusion
Above estimation of losses are approximate
due to various assumptions as under
There is no Friction and
Windage loss in transformer and block rotor condition of motor but it is
ignored in other conditions also. These losses are comparatively meager but not zero.
Current during no load (open
circuit) is very small but not zero. Copper loss is proportional to square of
the current and hence ignored.
Supply voltage during short
circuit (block rotor) is very low but not zero. Iron loss is proportional to
square of the voltage and hence ignored.
Dielectric and Stray loss are also
ignored.
Perfect estimation of all these
losses is very complex exercise.
In addition to basic findings of losses as above, other
parameters of machine can be derived graphically from above test data.
Fixed losses can also be estimated graphically by series of reading with different applied voltages.
Summary – Common
Identical Test Conditions
Test A, Min load -> No load, Open Circuit, Free Spinning
but No Output.
Test B, Max load -> Rated load, Short Circuit, Blocked Spin but No Output.